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Author Topic: A2000 R914 resistor (keyboard problem)  (Read 3595 times)

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Offline fjudde

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Re: A2000 R914 resistor (keyboard problem)
« on: November 01, 2015, 03:37:00 PM »
If you have two 2ohm resistors you can attach them in parallel, That will result in a 1ohm/0.5w resistor. If you have the physical space for it, and the soldering skills of course.
 

Offline fjudde

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Re: A2000 R914 resistor (keyboard problem)
« Reply #1 on: November 01, 2015, 11:27:16 PM »
Quote from: duga;798613
Thanks. It reads, after "jumping" for a while, 14 M ohms. Yes, 14 M ohms. Not 14 K ohms or 14 ohms.


That's a very high value! time for replacement! Try to find 1W or higher instead of .5W. It will hopefully prevent the resistor from running to hot and eventually fail.

If you can't find any soon enough and if you have att least four (4) 1 Ohm/.25W resistors you can build your own 1 ohm/1W.

2 in parallel gives you .5 Ohm/.5W

another 2 in parallel gives you another .5 Ohm/.5W

Now put these two 0.5 Ohms in series with each other and you get 1 ohm/1W.