I'm looking to put some ram on my a2091, which according to amigaresource would be 4x256k dip. However, the card has 16 sockets and a max of 2 MB...Wouldn't that be 4 MB of ram if each chip was 256k??
The chips are 256 kilobits, 4 bits wide. 1 byte = 8 bits so you'll need two chips to give 256 kilobytes.
Zorro II memory is 16 bits wide which means you'll have to add 4 chips in parallel (as they are 4 bits wide) 4x256x4= 256x16 = 512x8 (512 kiloBytes)
