I've never worked on such a thing, so the +80 and -80 volts coming out of it (with 110v AC going in to it) seemed somewhat reasonable. I had expected it to be +-60 volts, but whatever.
I forgot to mention....
The incoming AC mains is full wave rectified to DC by the bridge rectifier, and on the DC output of the bridge rectifier there will be one large electrolytic capacitor, or two in series.
The voltage across this reservoir capacitor will be the mains AC waveform peak voltage, less the forward voltage drop of two silicon diodes in the bridge rectifier.
i.e.
Vcapacitor = Vpeak - bridge rectifier fwd drop
Vcapacitor = Vrms / SIN(45) - (2 x 0.7V)
= 110V / SIN(45) - (2 x 0.7V)
= 155.6V - (2 x 0.7)
= 154V approx. across the reservior capacitor
If there are two reservior capacitors in series, there will be about 77V across each one. Hope that makes sense.