Am I correct in that, with the device powered on, I would touch one multi-meter probe to the circuit leg, and the other to ground to test if the proper voltage is coming out of that leg? The multimeter would be set to measure DV voltage. Is this correct?
Yes, that's correct.
Unless your multimeter is NOT a digital one, don't worry too much about range and polarity, it will simple display opposite sign or display over voltage. Nevertheless, try to use the black probe on GND and the red one on V+ and V- pins. Mine has ranges like 200mv, 2V, 20V, etc., in this case the correct range would be 20V. Just choose the first available range that's higher than the voltage you're going to measure.
Just looked at the datasheet again, we're lucky since all three pins are located on three corners, this way even if the chip is SO package, it should be farly easy to push probes over the pins from the respective outer side, without the risk of making shorts.
This is the complete pinout:
1 C1-
2 C2+
3 C2-
4 V- <= red probe here should read something near -10
5 GND <= black probe here for both measures
6 Vcc
7 C1+
8 V+ <= red probe here should read something near +10
The line on the chip is the "front" of it. Looking toward the front, pin 1 is the top-left one, pin 4 the bottom-left, 5 bottom-right, and 8 top-right.
Sorry if it's a bit pedantic, but at least I hope it's understandable!