Forgive the use of windows, but I need help !

[Einstein]

I've recently resumed (!) some C programming (in windows though), now the problem I've ran into is this: I'm trying to access a function through a pointer to it by declaring the pointer as void and then try to call the function with:


*funcPtr();

and:

*(funcPtr)();

and even:

(*(funcPtr))();

Yes, I realize I'm drunk ( :-D ), so tell me, how do I do ?

[Einstein]

Dammit people, why dont you respond ?  :-(

[Jose]

It's (* funcPtr)();

...

[Jose]

BTW, that probably won't work either I don't think C allows using a void * as a function pointer. Try to do some casting first.

[Einstein]

Thanx for your responce, however, what's casting ?

[Einstein]

Jose wrote:
BTW, that probably won't work either I don't think C allows using a void * as a function pointer.

That's pretty stupid is'nt it ? WHY wouldnt the compliler
allow such accessing one figures !!

[Einstein]

I'm still interested of help if you people wonder.  :-D

[Linchpin]

[countzero]

http://www.newty.de/fpt/fpt.html#defi

google and you shall find

casting is casting a type to a pointer. like, you can declare the function parameter as a void pointer, then you can cast it to a specific type and use it.

int myWindozeFunction (void * groovy, int what)

if (what == 1)
int * myIntPtr = (int *) groovy;

something like this...

[Einstein]

LinchpiN wrote:

I asked for a simple declaration for a function-pointer, not your inner and outer state in front of a mirror dude.  :-)

[Einstein]

countzero wrote:
http://www.newty.de/fpt/fpt.html#defi

google and you shall find

casting is casting a type to a pointer. like, you can declare the function parameter as a void pointer, then you can cast it to a specific type and use it.

int myWindozeFunction (void * groovy, int what)

if (what == 1)
int * myIntPtr = (int *) groovy;

something like this...

Thank you, appreciate the help.